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1、写出一个C程序,它能读入一个正整数n再逐行读入一个n*n的矩阵的元素(矩阵元素为整数,输入时相邻的整数用空格隔开),找出这个矩阵的最小的元素,再输出该元素的行号和列号(行号和列号均从1开始)。main()intn,i,j,a[80][80],min,min_i,min_j;printf(Pleaseintern=);scanf(%d,&n);printf(\\n);if(n<=0)printf(error:over limt!);elseprintf(Please intera:\\n);for(i=0;i
for (j=0;j
scanf(%d,&a[i][j]);min=a[0][0],min_i=0,min_j=0;for(i=0;i
for (j=0;j
if (max
min=a[i][j];
min_i=i;
min_j=j;printf(min_i=%d,min_j=%d\\n,min_i+1,min_j+1);2. 设 y(n)=1n<= 1时
if ((a[i]>=A)&&(a[i]<=Z)) n++;
i++;printf(n=%d\\n,n);
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